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13113350155 = 52622670031
BaseRepresentation
bin11000011011001110…
…11101100000001011
31020211220002012122101
430031213131200023
5203324004201110
610005120334231
7642650431363
oct141547354013
936756065571
1013113350155
11561a165074
12265b774377
13130ca0abb9
148c58339a3
1551b39213a
hex30d9dd80b

13113350155 has 4 divisors (see below), whose sum is σ = 15736020192. Its totient is φ = 10490680120.

The previous prime is 13113350119. The next prime is 13113350167. The reversal of 13113350155 is 55105331131.

13113350155 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 13113350155 - 221 = 13111253003 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1311335011 + ... + 1311335020.

It is an arithmetic number, because the mean of its divisors is an integer number (3934005048).

Almost surely, 213113350155 is an apocalyptic number.

13113350155 is a deficient number, since it is larger than the sum of its proper divisors (2622670037).

13113350155 is an equidigital number, since it uses as much as digits as its factorization.

13113350155 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2622670036.

The product of its (nonzero) digits is 3375, while the sum is 28.

Adding to 13113350155 its reverse (55105331131), we get a palindrome (68218681286).

The spelling of 13113350155 in words is "thirteen billion, one hundred thirteen million, three hundred fifty thousand, one hundred fifty-five".

Divisors: 1 5 2622670031 13113350155