1311341432433 has 16 divisors (see below), whose sum is σ = 1754390446080. Its totient is φ = 871261133184.

The previous prime is 1311341432417. The next prime is 1311341432459. The reversal of 1311341432433 is 3342341431131.

It is not a de Polignac number, because 1311341432433 - 2⁴ = 1311341432417 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1311341432394 and 1311341432403.

It is not an unprimeable number, because it can be changed into a prime (1311341432633) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4670335 + ... + 4943147.

It is an arithmetic number, because the mean of its divisors is an integer number (109649402880).

Almost surely, 2^{1311341432433} is an apocalyptic number.

It is an amenable number.

1311341432433 is a deficient number, since it is larger than the sum of its proper divisors (443049013647).

1311341432433 is a wasteful number, since it uses less digits than its factorization.

1311341432433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 278248.

The product of its digits is 31104, while the sum is 33.

Adding to 1311341432433 its reverse (3342341431131), we get a palindrome (4653682863564).

The spelling of 1311341432433 in words is "one trillion, three hundred eleven billion, three hundred forty-one million, four hundred thirty-two thousand, four hundred thirty-three".