13113553640147 has 4 divisors (see below), whose sum is σ = 13114488400320. Its totient is φ = 13112618879976.

The previous prime is 13113553640137. The next prime is 13113553640203. The reversal of 13113553640147 is 74104635531131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13113553640147 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13113553640098 and 13113553640107.

It is not an unprimeable number, because it can be changed into a prime (13113553640107) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 467359043 + ... + 467387100.

It is an arithmetic number, because the mean of its divisors is an integer number (3278622100080).

Almost surely, 2^{13113553640147} is an apocalyptic number.

13113553640147 is a deficient number, since it is larger than the sum of its proper divisors (934760173).

13113553640147 is an equidigital number, since it uses as much as digits as its factorization.

13113553640147 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 934760172.

The product of its (nonzero) digits is 453600, while the sum is 44.

The spelling of 13113553640147 in words is "thirteen trillion, one hundred thirteen billion, five hundred fifty-three million, six hundred forty thousand, one hundred forty-seven".