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13114103001443 = 71918239364397
BaseRepresentation
bin1011111011010101110101…
…1100110111000101100011
31201102200210101102120111222
42332311131130313011203
53204330140332021233
643520311415525255
72522314461201233
oct276653534670543
951380711376458
1013114103001443
1141a6729295594
12157972668982b
1374186822b712
14334a240d1cc3
1517b1dba9d898
hexbed5d737163

13114103001443 has 4 divisors (see below), whose sum is σ = 13132342366560. Its totient is φ = 13095863636328.

The previous prime is 13114103001409. The next prime is 13114103001463. The reversal of 13114103001443 is 34410030141131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13114103001443 - 28 = 13114103001187 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13114103001403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9119681480 + ... + 9119682917.

It is an arithmetic number, because the mean of its divisors is an integer number (3283085591640).

Almost surely, 213114103001443 is an apocalyptic number.

13114103001443 is a deficient number, since it is larger than the sum of its proper divisors (18239365117).

13114103001443 is an equidigital number, since it uses as much as digits as its factorization.

13114103001443 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18239365116.

The product of its (nonzero) digits is 1728, while the sum is 26.

Adding to 13114103001443 its reverse (34410030141131), we get a palindrome (47524133142574).

The spelling of 13114103001443 in words is "thirteen trillion, one hundred fourteen billion, one hundred three million, one thousand, four hundred forty-three".

Divisors: 1 719 18239364397 13114103001443