13114110134201 has 4 divisors (see below), whose sum is σ = 13684288835712. Its totient is φ = 12543931432692.

The previous prime is 13114110134189. The next prime is 13114110134261. The reversal of 13114110134201 is 10243101141131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13114110134201 - 2²⁶ = 13114043025337 is a prime.

It is a super-2 number, since 2×13114110134201² (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (23), and also a Moran number because the ratio is a prime number: 570178701487 = 13114110134201 / (1 + 3 + 1 + 1 + 4 + 1 + 1 + 0 + 1 + 3 + 4 + 2 + 0 + 1).

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13114110134261) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 285089350721 + ... + 285089350766.

It is an arithmetic number, because the mean of its divisors is an integer number (3421072208928).

Almost surely, 2^{13114110134201} is an apocalyptic number.

It is an amenable number.

13114110134201 is a deficient number, since it is larger than the sum of its proper divisors (570178701511).

13114110134201 is an equidigital number, since it uses as much as digits as its factorization.

13114110134201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 570178701510.

The product of its (nonzero) digits is 288, while the sum is 23.

Adding to 13114110134201 its reverse (10243101141131), we get a palindrome (23357211275332).

The spelling of 13114110134201 in words is "thirteen trillion, one hundred fourteen billion, one hundred ten million, one hundred thirty-four thousand, two hundred one".