13114111004003 has 8 divisors (see below), whose sum is σ = 13149972615600. Its totient is φ = 13078263607200.

The previous prime is 13114111003999. The next prime is 13114111004039. The reversal of 13114111004003 is 30040011141131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13114111004003 - 2² = 13114111003999 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13114111004063) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1704728 + ... + 5397621.

It is an arithmetic number, because the mean of its divisors is an integer number (1643746576950).

Almost surely, 2^{13114111004003} is an apocalyptic number.

13114111004003 is a deficient number, since it is larger than the sum of its proper divisors (35861611597).

13114111004003 is an equidigital number, since it uses as much as digits as its factorization.

13114111004003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7107397.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 13114111004003 its reverse (30040011141131), we get a palindrome (43154122145134).

The spelling of 13114111004003 in words is "thirteen trillion, one hundred fourteen billion, one hundred eleven million, four thousand, three".