131141111200331 has 4 divisors (see below), whose sum is σ = 131141134148832. Its totient is φ = 131141088251832.

The previous prime is 131141111200283. The next prime is 131141111200357. The reversal of 131141111200331 is 133002111141131.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 131141111200331 - 2²⁶ = 131141044091467 is a prime.

It is a super-2 number, since 2×131141111200331² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131141111200297 and 131141111200306.

It is not an unprimeable number, because it can be changed into a prime (131141111200531) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4658270 + ... + 16851756.

It is an arithmetic number, because the mean of its divisors is an integer number (32785283537208).

Almost surely, 2^{131141111200331} is an apocalyptic number.

131141111200331 is a deficient number, since it is larger than the sum of its proper divisors (22948501).

131141111200331 is a wasteful number, since it uses less digits than its factorization.

131141111200331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22948500.

The product of its (nonzero) digits is 216, while the sum is 23.

Adding to 131141111200331 its reverse (133002111141131), we get a palindrome (264143222341462).

The spelling of 131141111200331 in words is "one hundred thirty-one trillion, one hundred forty-one billion, one hundred eleven million, two hundred thousand, three hundred thirty-one".