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1311411130123 = 5979121933253
BaseRepresentation
bin10011000101010110001…
…100011100111100001011
311122100222111101220222011
4103011112030130330023
5132441232222130443
62442242015440351
7163513663453333
oct23052614347413
94570874356864
101311411130123
11466191438146
121921b0b260b7
139688625c443
1447688cba0c3
15241a5b25b9d
hex1315631cf0b

1311411130123 has 4 divisors (see below), whose sum is σ = 1311433123168. Its totient is φ = 1311389137080.

The previous prime is 1311411130067. The next prime is 1311411130147. The reversal of 1311411130123 is 3210311141131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1311411130123 - 213 = 1311411121931 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1311411130094 and 1311411130103.

It is not an unprimeable number, because it can be changed into a prime (1311411130153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10906836 + ... + 11026417.

It is an arithmetic number, because the mean of its divisors is an integer number (327858280792).

Almost surely, 21311411130123 is an apocalyptic number.

1311411130123 is a deficient number, since it is larger than the sum of its proper divisors (21993045).

1311411130123 is an equidigital number, since it uses as much as digits as its factorization.

1311411130123 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21993044.

The product of its (nonzero) digits is 216, while the sum is 22.

Adding to 1311411130123 its reverse (3210311141131), we get a palindrome (4521722271254).

The spelling of 1311411130123 in words is "one trillion, three hundred eleven billion, four hundred eleven million, one hundred thirty thousand, one hundred twenty-three".

Divisors: 1 59791 21933253 1311411130123