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13114112013203 = 69149333384701
BaseRepresentation
bin1011111011010101110111…
…1111001111001110010011
31201102200211000101102022212
42332311131333033032103
53204330200133410303
643520312341022335
72522314630613465
oct276653577171623
951380730342285
1013114112013203
1141a6733390223
1215797296b49ab
1374186a065516
14334a2539a135
1517b1dc77dad8
hexbed5dfcf393

13114112013203 has 8 divisors (see below), whose sum is σ = 13133390819856. Its totient is φ = 13094834076000.

The previous prime is 13114112013161. The next prime is 13114112013251. The reversal of 13114112013203 is 30231021141131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13114112013203 - 232 = 13109817045907 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13114112013103) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 33896753 + ... + 34281453.

It is an arithmetic number, because the mean of its divisors is an integer number (1641673852482).

Almost surely, 213114112013203 is an apocalyptic number.

13114112013203 is a deficient number, since it is larger than the sum of its proper divisors (19278806653).

13114112013203 is an equidigital number, since it uses as much as digits as its factorization.

13114112013203 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 434725.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 13114112013203 its reverse (30231021141131), we get a palindrome (43345133154334).

The spelling of 13114112013203 in words is "thirteen trillion, one hundred fourteen billion, one hundred twelve million, thirteen thousand, two hundred three".

Divisors: 1 691 49333 384701 34089103 265828391 18978454433 13114112013203