13114114131 has 4 divisors (see below), whose sum is σ = 17485485512. Its totient is φ = 8742742752.

The previous prime is 13114114121. The next prime is 13114114151. The reversal of 13114114131 is 13141141131.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 13114114131 - 2⁷ = 13114114003 is a prime.

It is a super-2 number, since 2×13114114131² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13114114098 and 13114114107.

It is not an unprimeable number, because it can be changed into a prime (13114114121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2185685686 + ... + 2185685691.

It is an arithmetic number, because the mean of its divisors is an integer number (4371371378).

Almost surely, 2^13114114131 is an apocalyptic number.

13114114131 is a deficient number, since it is larger than the sum of its proper divisors (4371371381).

13114114131 is an equidigital number, since it uses as much as digits as its factorization.

13114114131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4371371380.

The product of its digits is 144, while the sum is 21.

Adding to 13114114131 its reverse (13141141131), we get a palindrome (26255255262).

The spelling of 13114114131 in words is "thirteen billion, one hundred fourteen million, one hundred fourteen thousand, one hundred thirty-one".