13114125121 has 4 divisors (see below), whose sum is σ = 13122945792. Its totient is φ = 13105304452.

The previous prime is 13114125049. The next prime is 13114125127. The reversal of 13114125121 is 12152141131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 12152141131 = 13 ⋅934780087.

It is a cyclic number.

It is not a de Polignac number, because 13114125121 - 2¹³ = 13114116929 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13114125092 and 13114125101.

It is not an unprimeable number, because it can be changed into a prime (13114125127) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4408105 + ... + 4411078.

It is an arithmetic number, because the mean of its divisors is an integer number (3280736448).

Almost surely, 2^13114125121 is an apocalyptic number.

It is an amenable number.

13114125121 is a deficient number, since it is larger than the sum of its proper divisors (8820671).

13114125121 is an equidigital number, since it uses as much as digits as its factorization.

13114125121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8820670.

The product of its digits is 240, while the sum is 22.

Adding to 13114125121 its reverse (12152141131), we get a palindrome (25266266252).

The spelling of 13114125121 in words is "thirteen billion, one hundred fourteen million, one hundred twenty-five thousand, one hundred twenty-one".