131141324001001 has 4 divisors (see below), whose sum is σ = 131141353563792. Its totient is φ = 131141294438212.

The previous prime is 131141324000989. The next prime is 131141324001011. The reversal of 131141324001001 is 100100423141131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131141324001001 - 2³³ = 131132734066409 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131141324001011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6628351 + ... + 17499076.

It is an arithmetic number, because the mean of its divisors is an integer number (32785338390948).

Almost surely, 2^{131141324001001} is an apocalyptic number.

It is an amenable number.

131141324001001 is a deficient number, since it is larger than the sum of its proper divisors (29562791).

131141324001001 is an equidigital number, since it uses as much as digits as its factorization.

131141324001001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 29562790.

The product of its (nonzero) digits is 288, while the sum is 22.

Adding to 131141324001001 its reverse (100100423141131), we get a palindrome (231241747142132).

The spelling of 131141324001001 in words is "one hundred thirty-one trillion, one hundred forty-one billion, three hundred twenty-four million, one thousand, one".