131141324423433 has 4 divisors (see below), whose sum is σ = 174855099231248. Its totient is φ = 87427549615620.

The previous prime is 131141324423393. The next prime is 131141324423437. The reversal of 131141324423433 is 334324423141131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 131141324423433 - 2¹⁷ = 131141324292361 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131141324423391 and 131141324423400.

It is not an unprimeable number, because it can be changed into a prime (131141324423437) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21856887403903 + ... + 21856887403908.

It is an arithmetic number, because the mean of its divisors is an integer number (43713774807812).

Almost surely, 2^{131141324423433} is an apocalyptic number.

It is an amenable number.

131141324423433 is a deficient number, since it is larger than the sum of its proper divisors (43713774807815).

131141324423433 is an equidigital number, since it uses as much as digits as its factorization.

131141324423433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43713774807814.

The product of its digits is 248832, while the sum is 39.

Adding to 131141324423433 its reverse (334324423141131), we get a palindrome (465465747564564).

The spelling of 131141324423433 in words is "one hundred thirty-one trillion, one hundred forty-one billion, three hundred twenty-four million, four hundred twenty-three thousand, four hundred thirty-three".