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131141403413203 = 313418982119531
BaseRepresentation
bin11101110100010110111100…
…110001000000101011010011
3122012022222212212220100222211
4131310112330301000223103
5114142110043233210303
61142525310134212551
736423440141506501
oct3564267461005323
9565288785810884
10131141403413203
1138870836417387
12128600ba7b4157
1358237730b7c11
1424553c6393671
15102644ed4c66d
hex7745bcc40ad3

131141403413203 has 4 divisors (see below), whose sum is σ = 131560385533048. Its totient is φ = 130722421293360.

The previous prime is 131141403413201. The next prime is 131141403413227. The reversal of 131141403413203 is 302314304141131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131141403413203 - 21 = 131141403413201 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131141403413201) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 209491059453 + ... + 209491060078.

It is an arithmetic number, because the mean of its divisors is an integer number (32890096383262).

Almost surely, 2131141403413203 is an apocalyptic number.

131141403413203 is a deficient number, since it is larger than the sum of its proper divisors (418982119845).

131141403413203 is an equidigital number, since it uses as much as digits as its factorization.

131141403413203 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 418982119844.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 131141403413203 its reverse (302314304141131), we get a palindrome (433455707554334).

The spelling of 131141403413203 in words is "one hundred thirty-one trillion, one hundred forty-one billion, four hundred three million, four hundred thirteen thousand, two hundred three".

Divisors: 1 313 418982119531 131141403413203