Base | Representation |
---|---|
bin | 11101110100010110111110… |
… | …011010010011001001110011 |
3 | 122012022222221210211122011200 |
4 | 131310112332122103021303 |
5 | 114142110122314422003 |
6 | 1142525313001542243 |
7 | 36423440625223344 |
oct | 3564267632231163 |
9 | 565288853748150 |
10 | 131141431014003 |
11 | 3887084aa59263 |
12 | 12860107aa4983 |
13 | 5823778a2cb57 |
14 | 24553c9cda0cb |
15 | 10264524a06a3 |
hex | 7745be693273 |
131141431014003 has 12 divisors (see below), whose sum is σ = 189570125213040. Its totient is φ = 87361337407536.
The previous prime is 131141431013987. The next prime is 131141431014007. The reversal of 131141431014003 is 300410134141131.
131141431014003 is a `hidden beast` number, since 1 + 3 + 1 + 14 + 143 + 101 + 400 + 3 = 666.
It is not a de Polignac number, because 131141431014003 - 24 = 131141431013987 is a prime.
It is not an unprimeable number, because it can be changed into a prime (131141431014007) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 5523593176 + ... + 5523616917.
It is an arithmetic number, because the mean of its divisors is an integer number (15797510434420).
Almost surely, 2131141431014003 is an apocalyptic number.
131141431014003 is a deficient number, since it is larger than the sum of its proper divisors (58428694199037).
131141431014003 is a wasteful number, since it uses less digits than its factorization.
131141431014003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11047211418 (or 11047211415 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 27.
Adding to 131141431014003 its reverse (300410134141131), we get a palindrome (431551565155134).
The spelling of 131141431014003 in words is "one hundred thirty-one trillion, one hundred forty-one billion, four hundred thirty-one million, fourteen thousand, three".
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