Base | Representation |
---|---|
bin | 1011111011010101111111… |
… | …1001101100000101101011 |
3 | 1201102200220020210020222100 |
4 | 2332311133321230011223 |
5 | 3204330231343104003 |
6 | 43520315445024443 |
7 | 2522315500506063 |
oct | 276653771540553 |
9 | 51380806706870 |
10 | 13114144113003 |
11 | 41a674a51528a |
12 | 15797383b5123 |
13 | 7418738c419b |
14 | 334a297543a3 |
15 | 17b1e04beba3 |
hex | bed5fe6c16b |
13114144113003 has 6 divisors (see below), whose sum is σ = 18942652607684. Its totient is φ = 8742762741996.
The previous prime is 13114144112999. The next prime is 13114144113041. The reversal of 13114144113003 is 30031144141131.
13114144113003 is a `hidden beast` number, since 1 + 311 + 4 + 1 + 4 + 41 + 1 + 300 + 3 = 666.
It is not a de Polignac number, because 13114144113003 - 22 = 13114144112999 is a prime.
It is a super-2 number, since 2×131141441130032 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13114144114003) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 728563561825 + ... + 728563561842.
Almost surely, 213114144113003 is an apocalyptic number.
13114144113003 is a deficient number, since it is larger than the sum of its proper divisors (5828508494681).
13114144113003 is a wasteful number, since it uses less digits than its factorization.
13114144113003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1457127123673 (or 1457127123670 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 27.
Adding to 13114144113003 its reverse (30031144141131), we get a palindrome (43145288254134).
The spelling of 13114144113003 in words is "thirteen trillion, one hundred fourteen billion, one hundred forty-four million, one hundred thirteen thousand, three".
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