131142121041 has 4 divisors (see below), whose sum is σ = 174856161392. Its totient is φ = 87428080692.

The previous prime is 131142121039. The next prime is 131142121051. The reversal of 131142121041 is 140121241131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 131142121041 - 2¹ = 131142121039 is a prime.

It is a super-2 number, since 2×131142121041² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131142120999 and 131142121017.

It is not an unprimeable number, because it can be changed into a prime (131142121051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21857020171 + ... + 21857020176.

It is an arithmetic number, because the mean of its divisors is an integer number (43714040348).

Almost surely, 2^131142121041 is an apocalyptic number.

It is an amenable number.

131142121041 is a deficient number, since it is larger than the sum of its proper divisors (43714040351).

131142121041 is an equidigital number, since it uses as much as digits as its factorization.

131142121041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43714040350.

The product of its (nonzero) digits is 192, while the sum is 21.

Adding to 131142121041 its reverse (140121241131), we get a palindrome (271263362172).

The spelling of 131142121041 in words is "one hundred thirty-one billion, one hundred forty-two million, one hundred twenty-one thousand, forty-one".