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1311423362339 = 4195273125957
BaseRepresentation
bin10011000101010110111…
…011000111010100100011
311122101000100102101102012
4103011112323013110203
5132441243340043324
62442243133543135
7163514202440636
oct23052673072443
94571010371365
101311423362339
11466198332412
121921b5044aab
139688895303c
144768a781c1d
15241a6c4020e
hex13156ec7523

1311423362339 has 4 divisors (see below), whose sum is σ = 1311426907824. Its totient is φ = 1311419816856.

The previous prime is 1311423362317. The next prime is 1311423362363. The reversal of 1311423362339 is 9332633241131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1311423362339 - 28 = 1311423362083 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1311423362296 and 1311423362305.

It is not an unprimeable number, because it can be changed into a prime (1311423362239) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1143452 + ... + 1982505.

It is an arithmetic number, because the mean of its divisors is an integer number (327856726956).

Almost surely, 21311423362339 is an apocalyptic number.

1311423362339 is a deficient number, since it is larger than the sum of its proper divisors (3545485).

1311423362339 is an equidigital number, since it uses as much as digits as its factorization.

1311423362339 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3545484.

The product of its digits is 209952, while the sum is 41.

The spelling of 1311423362339 in words is "one trillion, three hundred eleven billion, four hundred twenty-three million, three hundred sixty-two thousand, three hundred thirty-nine".

Divisors: 1 419527 3125957 1311423362339