13114244003 has 4 divisors (see below), whose sum is σ = 14987707440. Its totient is φ = 11240780568.

The previous prime is 13114243993. The next prime is 13114244053. The reversal of 13114244003 is 30044241131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13114244003 - 2¹⁰ = 13114242979 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13114244003.

It is not an unprimeable number, because it can be changed into a prime (13114244053) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 936731708 + ... + 936731721.

It is an arithmetic number, because the mean of its divisors is an integer number (3746926860).

Almost surely, 2^13114244003 is an apocalyptic number.

13114244003 is a deficient number, since it is larger than the sum of its proper divisors (1873463437).

13114244003 is an equidigital number, since it uses as much as digits as its factorization.

13114244003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1873463436.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 13114244003 its reverse (30044241131), we get a palindrome (43158485134).

The spelling of 13114244003 in words is "thirteen billion, one hundred fourteen million, two hundred forty-four thousand, three".