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131143202043403 = 1129411107216437
BaseRepresentation
bin11101110100011000100111…
…111110001111011000001011
3122012100011112020100020210011
4131310120213332033120023
5114142122234210342103
61142530204425132351
736423532541560354
oct3564304776173013
9565304466306704
10131143202043403
1138871579725920
121286052102a0b7
13582399b918644
1424555171d0d2b
151026507bd4d6d
hex774627f8f60b

131143202043403 has 8 divisors (see below), whose sum is σ = 147998597917680. Its totient is φ = 115110020602080.

The previous prime is 131143202043397. The next prime is 131143202043433. The reversal of 131143202043403 is 304340202341131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131143202043403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131143202043433) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 205553607900 + ... + 205553608537.

It is an arithmetic number, because the mean of its divisors is an integer number (18499824739710).

Almost surely, 2131143202043403 is an apocalyptic number.

131143202043403 is a deficient number, since it is larger than the sum of its proper divisors (16855395874277).

131143202043403 is a wasteful number, since it uses less digits than its factorization.

131143202043403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 411107216477.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 131143202043403 its reverse (304340202341131), we get a palindrome (435483404384534).

The spelling of 131143202043403 in words is "one hundred thirty-one trillion, one hundred forty-three billion, two hundred two million, forty-three thousand, four hundred three".

Divisors: 1 11 29 319 411107216437 4522179380807 11922109276673 131143202043403