1311433430401 has 4 divisors (see below), whose sum is σ = 1312270339072. Its totient is φ = 1310596521732.

The previous prime is 1311433430369. The next prime is 1311433430443. The reversal of 1311433430401 is 1040343341131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1311433430401 - 2⁵ = 1311433430369 is a prime.

It is a super-2 number, since 2×1311433430401² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1311433430401.

It is not an unprimeable number, because it can be changed into a prime (1311433400401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 418451985 + ... + 418455118.

It is an arithmetic number, because the mean of its divisors is an integer number (328067584768).

Almost surely, 2^{1311433430401} is an apocalyptic number.

It is an amenable number.

1311433430401 is a deficient number, since it is larger than the sum of its proper divisors (836908671).

1311433430401 is an equidigital number, since it uses as much as digits as its factorization.

1311433430401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 836908670.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 1311433430401 its reverse (1040343341131), we get a palindrome (2351776771532).

The spelling of 1311433430401 in words is "one trillion, three hundred eleven billion, four hundred thirty-three million, four hundred thirty thousand, four hundred one".