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13114334340411 = 34989187619907
BaseRepresentation
bin1011111011010110101100…
…1111010110010100111011
31201102201101111201210220220
42332311223033112110323
53204331124042343121
643520350402151123
72522323300431663
oct276655317262473
951381344653826
1013114334340411
1141a6837932a17
1215797900524a3
137418a4139295
14334a46b111a3
1517b2020486c6
hexbed6b3d653b

13114334340411 has 8 divisors (see below), whose sum is σ = 17486129799744. Its totient is φ = 8742714220680.

The previous prime is 13114334340353. The next prime is 13114334340431. The reversal of 13114334340411 is 11404343341131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2k-13114334340411 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13114334340431) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 43660281 + ... + 43959626.

It is an arithmetic number, because the mean of its divisors is an integer number (2185766224968).

Almost surely, 213114334340411 is an apocalyptic number.

13114334340411 is a deficient number, since it is larger than the sum of its proper divisors (4371795459333).

13114334340411 is an equidigital number, since it uses as much as digits as its factorization.

13114334340411 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 87669801.

The product of its (nonzero) digits is 20736, while the sum is 33.

Adding to 13114334340411 its reverse (11404343341131), we get a palindrome (24518677681542).

The spelling of 13114334340411 in words is "thirteen trillion, one hundred fourteen billion, three hundred thirty-four million, three hundred forty thousand, four hundred eleven".

Divisors: 1 3 49891 149673 87619907 262859721 4371444780137 13114334340411