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1311434056435 = 5299044372803
BaseRepresentation
bin10011000101010111100…
…011111010001011110011
311122101001002112200221211
4103011113203322023303
5132441304104301220
62442244155100551
7163514362361026
oct23052743721363
94571032480854
101311434056435
114661a3377008
121921b8741757
139688ac287c9
144768bd671bd
15241a7b53b5a
hex131578fa2f3

1311434056435 has 8 divisors (see below), whose sum is σ = 1627987104720. Its totient is φ = 1012969753824.

The previous prime is 1311434056417. The next prime is 1311434056469. The reversal of 1311434056435 is 5346504341131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1311434056435 - 215 = 1311434023667 is a prime.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4522186257 + ... + 4522186546.

It is an arithmetic number, because the mean of its divisors is an integer number (203498388090).

Almost surely, 21311434056435 is an apocalyptic number.

1311434056435 is a deficient number, since it is larger than the sum of its proper divisors (316553048285).

1311434056435 is an equidigital number, since it uses as much as digits as its factorization.

1311434056435 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9044372837.

The product of its (nonzero) digits is 259200, while the sum is 40.

Adding to 1311434056435 its reverse (5346504341131), we get a palindrome (6657938397566).

The spelling of 1311434056435 in words is "one trillion, three hundred eleven billion, four hundred thirty-four million, fifty-six thousand, four hundred thirty-five".

Divisors: 1 5 29 145 9044372803 45221864015 262286811287 1311434056435