1311434200001 has 4 divisors (see below), whose sum is σ = 1311864322500. Its totient is φ = 1311004077504.

The previous prime is 1311434199997. The next prime is 1311434200031. The reversal of 1311434200001 is 1000024341131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 55243801600 + 1256190398401 = 235040^2 + 1120799^2 .

It is a cyclic number.

It is not a de Polignac number, because 1311434200001 - 2² = 1311434199997 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1311434200031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 215056676 + ... + 215062773.

It is an arithmetic number, because the mean of its divisors is an integer number (327966080625).

Almost surely, 2^{1311434200001} is an apocalyptic number.

It is an amenable number.

1311434200001 is a deficient number, since it is larger than the sum of its proper divisors (430122499).

1311434200001 is an equidigital number, since it uses as much as digits as its factorization.

1311434200001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 430122498.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 1311434200001 its reverse (1000024341131), we get a palindrome (2311458541132).

The spelling of 1311434200001 in words is "one trillion, three hundred eleven billion, four hundred thirty-four million, two hundred thousand, one".