131144211041 has 4 divisors (see below), whose sum is σ = 132176842752. Its totient is φ = 130111579332.

The previous prime is 131144210999. The next prime is 131144211047. The reversal of 131144211041 is 140112441131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131144211041 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131144210998 and 131144211016.

It is not an unprimeable number, because it can be changed into a prime (131144211047) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 516315665 + ... + 516315918.

It is an arithmetic number, because the mean of its divisors is an integer number (33044210688).

Almost surely, 2^131144211041 is an apocalyptic number.

It is an amenable number.

131144211041 is a deficient number, since it is larger than the sum of its proper divisors (1032631711).

131144211041 is a wasteful number, since it uses less digits than its factorization.

131144211041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1032631710.

The product of its (nonzero) digits is 384, while the sum is 23.

Adding to 131144211041 its reverse (140112441131), we get a palindrome (271256652172).

The spelling of 131144211041 in words is "one hundred thirty-one billion, one hundred forty-four million, two hundred eleven thousand, forty-one".