Base | Representation |
---|---|
bin | 1011111011010111101010… |
… | …1111100001100001101011 |
3 | 1201102202001122010220001121 |
4 | 2332311322233201201223 |
5 | 3204332142133330011 |
6 | 43520432253000111 |
7 | 2522332606250542 |
oct | 276657257414153 |
9 | 51382048126047 |
10 | 13114594433131 |
11 | 41a696072a484 |
12 | 1579843183037 |
13 | 741915ca37b9 |
14 | 334a6d497159 |
15 | 17b219cc2e71 |
hex | bed7abe186b |
13114594433131 has 8 divisors (see below), whose sum is σ = 13120550299584. Its totient is φ = 13108639642560.
The previous prime is 13114594433113. The next prime is 13114594433173. The reversal of 13114594433131 is 13133449541131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13114594433131 - 29 = 13114594432619 is a prime.
It is a super-2 number, since 2×131145944331312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13114594433231) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 24637111 + ... + 25163791.
It is an arithmetic number, because the mean of its divisors is an integer number (1640068787448).
Almost surely, 213114594433131 is an apocalyptic number.
13114594433131 is a deficient number, since it is larger than the sum of its proper divisors (5955866453).
13114594433131 is an equidigital number, since it uses as much as digits as its factorization.
13114594433131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 537941.
The product of its digits is 233280, while the sum is 43.
The spelling of 13114594433131 in words is "thirteen trillion, one hundred fourteen billion, five hundred ninety-four million, four hundred thirty-three thousand, one hundred thirty-one".
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