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131152133341555 = 563014162899011
BaseRepresentation
bin11101110100100000111100…
…010100011100000101110011
3122012101000120200011012120121
4131310200330110130011303
5114142244032113412210
61142534242553551111
736424300061422444
oct3564407424340563
9565330520135517
10131152133341555
1138875342162367
12128621b4115497
135824793092c51
142455b234412cb
15102687bd406da
hex77483c51c173

131152133341555 has 8 divisors (see below), whose sum is σ = 157407537441744. Its totient is φ = 104905055052000.

The previous prime is 131152133341547. The next prime is 131152133341571. The reversal of 131152133341555 is 555143331251131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 131152133341555 - 23 = 131152133341547 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2081418001 + ... + 2081481010.

It is an arithmetic number, because the mean of its divisors is an integer number (19675942180218).

Almost surely, 2131152133341555 is an apocalyptic number.

131152133341555 is a deficient number, since it is larger than the sum of its proper divisors (26255404100189).

131152133341555 is an equidigital number, since it uses as much as digits as its factorization.

131152133341555 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4162905317.

The product of its digits is 405000, while the sum is 43.

Adding to 131152133341555 its reverse (555143331251131), we get a palindrome (686295464592686).

The spelling of 131152133341555 in words is "one hundred thirty-one trillion, one hundred fifty-two billion, one hundred thirty-three million, three hundred forty-one thousand, five hundred fifty-five".

Divisors: 1 5 6301 31505 4162899011 20814495055 26230426668311 131152133341555