Base | Representation |
---|---|
bin | 10011000101011100110… |
… | …011100011100011110001 |
3 | 11122101021020002221101220 |
4 | 103011130303203203301 |
5 | 132441444120403040 |
6 | 2442301021015253 |
7 | 163516511302665 |
oct | 23053463434361 |
9 | 4571236087356 |
10 | 1311522044145 |
11 | 466239003525 |
12 | 1922220b4529 |
13 | 968a3224841 |
14 | 4769990c8a5 |
15 | 241b07342d0 |
hex | 1315cce38f1 |
1311522044145 has 8 divisors (see below), whose sum is σ = 2098435270656. Its totient is φ = 699478423536.
The previous prime is 1311522044137. The next prime is 1311522044153. The reversal of 1311522044145 is 5414402251131.
It is an interprime number because it is at equal distance from previous prime (1311522044137) and next prime (1311522044153).
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1311522044145 - 23 = 1311522044137 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 43717401457 + ... + 43717401486.
It is an arithmetic number, because the mean of its divisors is an integer number (262304408832).
Almost surely, 21311522044145 is an apocalyptic number.
1311522044145 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1311522044145 is a deficient number, since it is larger than the sum of its proper divisors (786913226511).
1311522044145 is an equidigital number, since it uses as much as digits as its factorization.
1311522044145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 87434802951.
The product of its (nonzero) digits is 19200, while the sum is 33.
Adding to 1311522044145 its reverse (5414402251131), we get a palindrome (6725924295276).
The spelling of 1311522044145 in words is "one trillion, three hundred eleven billion, five hundred twenty-two million, forty-four thousand, one hundred forty-five".
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