Base | Representation |
---|---|
bin | 1011111011011010001010… |
… | …0101011101111010100001 |
3 | 1201102210210012221210101010 |
4 | 2332312202211131322201 |
5 | 3204340024244314122 |
6 | 43521022452131133 |
7 | 2522355304066431 |
oct | 276664245357241 |
9 | 51383705853333 |
10 | 13115262885537 |
11 | 41a7173a9168a |
12 | 15799ab006aa9 |
13 | 7419c1618677 |
14 | 334ad417c2c1 |
15 | 17b258812e0c |
hex | beda295dea1 |
13115262885537 has 4 divisors (see below), whose sum is σ = 17487017180720. Its totient is φ = 8743508590356.
The previous prime is 13115262885521. The next prime is 13115262885643. The reversal of 13115262885537 is 73558826251131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 13115262885537 - 24 = 13115262885521 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13115262885337) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2185877147587 + ... + 2185877147592.
It is an arithmetic number, because the mean of its divisors is an integer number (4371754295180).
Almost surely, 213115262885537 is an apocalyptic number.
It is an amenable number.
13115262885537 is a deficient number, since it is larger than the sum of its proper divisors (4371754295183).
13115262885537 is an equidigital number, since it uses as much as digits as its factorization.
13115262885537 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4371754295182.
The product of its digits is 12096000, while the sum is 57.
The spelling of 13115262885537 in words is "thirteen trillion, one hundred fifteen billion, two hundred sixty-two million, eight hundred eighty-five thousand, five hundred thirty-seven".
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