Base | Representation |
---|---|
bin | 11101110100100010000011… |
… | …000100011001110011110001 |
3 | 122012101010122101122222020011 |
4 | 131310202003010121303301 |
5 | 114142304000000221431 |
6 | 1142535000435014521 |
7 | 36424341353525632 |
oct | 3564420304316361 |
9 | 565333571588204 |
10 | 131153320320241 |
11 | 388758a1184a8a |
12 | 1286248573a441 |
13 | 5824921c785bb |
14 | 2455bd6d41889 |
15 | 10268eb157cb1 |
hex | 774883119cf1 |
131153320320241 has 8 divisors (see below), whose sum is σ = 131511207203840. Its totient is φ = 130795436268288.
The previous prime is 131153320320203. The next prime is 131153320320349. The reversal of 131153320320241 is 142023023351131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 131153320320241 - 233 = 131144730385649 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131153320320541) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 120161920 + ... + 121248478.
It is an arithmetic number, because the mean of its divisors is an integer number (16438900900480).
Almost surely, 2131153320320241 is an apocalyptic number.
It is an amenable number.
131153320320241 is a deficient number, since it is larger than the sum of its proper divisors (357886883599).
131153320320241 is a wasteful number, since it uses less digits than its factorization.
131153320320241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1415823.
The product of its (nonzero) digits is 12960, while the sum is 31.
Adding to 131153320320241 its reverse (142023023351131), we get a palindrome (273176343671372).
The spelling of 131153320320241 in words is "one hundred thirty-one trillion, one hundred fifty-three billion, three hundred twenty million, three hundred twenty thousand, two hundred forty-one".
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