131161000153 has 4 divisors (see below), whose sum is σ = 131212579968. Its totient is φ = 131109420340.

The previous prime is 131161000049. The next prime is 131161000169. The reversal of 131161000153 is 351000161131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131161000153 is a prime.

It is a super-2 number, since 2×131161000153² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131161000183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25786093 + ... + 25791178.

It is an arithmetic number, because the mean of its divisors is an integer number (32803144992).

Almost surely, 2^131161000153 is an apocalyptic number.

131161000153 is the 193584-th centered heptagonal number.

It is an amenable number.

131161000153 is a deficient number, since it is larger than the sum of its proper divisors (51579815).

131161000153 is an equidigital number, since it uses as much as digits as its factorization.

131161000153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 51579814.

The product of its (nonzero) digits is 270, while the sum is 22.

Adding to 131161000153 its reverse (351000161131), we get a palindrome (482161161284).

The spelling of 131161000153 in words is "one hundred thirty-one billion, one hundred sixty-one million, one hundred fifty-three", and thus it is an aban number.