13117138254081 has 27 divisors (see below), whose sum is σ = 19138029786057. Its totient is φ = 8657452713600.

The previous prime is 13117138254029. The next prime is 13117138254089. The reversal of 13117138254081 is 18045283171131.

The square root of 13117138254081 is 3621759.

It is a perfect power (a square), and thus also a powerful number.

13117138254081 is a `hidden beast` number, since 1 + 3 + 1 + 1 + 71 + 38 + 2 + 540 + 8 + 1 = 666.

13117138254081 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 4 ways, for example, as 9973311383025 + 3143826871056 = 3158055^2 + 1773084^2 .

It is a de Polignac number, because none of the positive numbers 2^k-13117138254081 is a prime.

It is a super-2 number, since 2×13117138254081² (a number of 27 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (13117138254089) by changing a digit.

It is a polite number, since it can be written in 26 ways as a sum of consecutive naturals, for example, 1097387001 + ... + 1097398953.

Almost surely, 2^{13117138254081} is an apocalyptic number.

13117138254081 is the 3621759-th square number.

13117138254081 is the 1810880-th centered octagonal number.

It is an amenable number.

13117138254081 is a deficient number, since it is larger than the sum of its proper divisors (6020891531976).

13117138254081 is an frugal number, since it uses more digits than its factorization.

13117138254081 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24114 (or 12057 counting only the distinct ones).

The product of its (nonzero) digits is 161280, while the sum is 45.

The spelling of 13117138254081 in words is "thirteen trillion, one hundred seventeen billion, one hundred thirty-eight million, two hundred fifty-four thousand, eighty-one".