Base | Representation |
---|---|
bin | 10011000101111001010… |
… | …011001100110000111001 |
3 | 11122102111112122202201101 |
4 | 103011321103030300321 |
5 | 132443434011221213 |
6 | 2442420255251401 |
7 | 163534404600010 |
oct | 23057123146071 |
9 | 4572445582641 |
10 | 1312000101433 |
11 | 466463942a9a |
12 | 192336219b61 |
13 | 9694b296188 |
14 | 477031d1a77 |
15 | 241dc6b5bdd |
hex | 131794ccc39 |
1312000101433 has 8 divisors (see below), whose sum is σ = 1564621239168. Its totient is φ = 1075677101664.
The previous prime is 1312000101383. The next prime is 1312000101449. The reversal of 1312000101433 is 3341010002131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1312000101433 - 233 = 1303410166841 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1312000101433.
It is not an unprimeable number, because it can be changed into a prime (1312000101463) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4074534316 + ... + 4074534637.
It is an arithmetic number, because the mean of its divisors is an integer number (195577654896).
Almost surely, 21312000101433 is an apocalyptic number.
It is an amenable number.
1312000101433 is a deficient number, since it is larger than the sum of its proper divisors (252621137735).
1312000101433 is an equidigital number, since it uses as much as digits as its factorization.
1312000101433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8149068983.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 1312000101433 its reverse (3341010002131), we get a palindrome (4653010103564).
The spelling of 1312000101433 in words is "one trillion, three hundred twelve billion, one hundred one thousand, four hundred thirty-three".
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