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131200233193 = 199933656221
BaseRepresentation
bin111101000110000100…
…1001010111011101001
3110112122120101102001001
41322030021022323221
54122144224430233
6140134512155001
712323156403331
oct1721411127351
9415576342031
10131200233193
1150707125097
1221516838a61
13c4ab74b1a3
1464c8a5a0c1
15362d3e827d
hex1e8c24aee9

131200233193 has 4 divisors (see below), whose sum is σ = 131201089348. Its totient is φ = 131199377040.

The previous prime is 131200233079. The next prime is 131200233211. The reversal of 131200233193 is 391332002131.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 77266209024 + 53934024169 = 277968^2 + 232237^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131200233193 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131200203193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 128178 + ... + 528043.

It is an arithmetic number, because the mean of its divisors is an integer number (32800272337).

Almost surely, 2131200233193 is an apocalyptic number.

It is an amenable number.

131200233193 is a deficient number, since it is larger than the sum of its proper divisors (856155).

131200233193 is an equidigital number, since it uses as much as digits as its factorization.

131200233193 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 856154.

The product of its (nonzero) digits is 2916, while the sum is 28.

The spelling of 131200233193 in words is "one hundred thirty-one billion, two hundred million, two hundred thirty-three thousand, one hundred ninety-three".

Divisors: 1 199933 656221 131200233193