Base | Representation |
---|---|
bin | 10011000101111001111… |
… | …100110001110111101011 |
3 | 11122102112022011112120000 |
4 | 103011321330301313223 |
5 | 132443444304020243 |
6 | 2442421325034043 |
7 | 163534566335061 |
oct | 23057174616753 |
9 | 4572468145500 |
10 | 1312011001323 |
11 | 46646a008270 |
12 | 1923399b5923 |
13 | 96950611509 |
14 | 4770482c031 |
15 | 241dd61a5d3 |
hex | 13179f31deb |
1312011001323 has 40 divisors (see below), whose sum is σ = 2138441741040. Its totient is φ = 795028115520.
The previous prime is 1312011001319. The next prime is 1312011001349. The reversal of 1312011001323 is 3231001102131.
1312011001323 is a `hidden beast` number, since 131 + 201 + 10 + 0 + 1 + 323 = 666.
It is not a de Polignac number, because 1312011001323 - 22 = 1312011001319 is a prime.
It is a super-2 number, since 2×13120110013232 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1312011001296 and 1312011001305.
It is not an unprimeable number, because it can be changed into a prime (1312011001123) by changing a digit.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 5475513 + ... + 5710101.
It is an arithmetic number, because the mean of its divisors is an integer number (53461043526).
Almost surely, 21312011001323 is an apocalyptic number.
1312011001323 is a deficient number, since it is larger than the sum of its proper divisors (826430739717).
1312011001323 is a wasteful number, since it uses less digits than its factorization.
1312011001323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 240889 (or 240880 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 18.
Adding to 1312011001323 its reverse (3231001102131), we get a palindrome (4543012103454).
The spelling of 1312011001323 in words is "one trillion, three hundred twelve billion, eleven million, one thousand, three hundred twenty-three".
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