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13120124202203 = 14994727929561
BaseRepresentation
bin1011111011101100010001…
…0101111010110011011011
31201110021100000101021011112
42332323010111322303123
53204430003243432303
643523145111050535
72522616623436344
oct276730425726333
951407300337145
1013120124202203
1141a9239086867
12157a927070a4b
137422b780b2c5
14335035a5d0cb
1517b4404c30d8
hexbeec457acdb

13120124202203 has 8 divisors (see below), whose sum is σ = 13208332370400. Its totient is φ = 13031918082880.

The previous prime is 13120124202167. The next prime is 13120124202221. The reversal of 13120124202203 is 30220242102131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13120124202203 - 26 = 13120124202139 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13120124282203) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 13649543 + ... + 14579103.

It is an arithmetic number, because the mean of its divisors is an integer number (1651041546300).

Almost surely, 213120124202203 is an apocalyptic number.

13120124202203 is a deficient number, since it is larger than the sum of its proper divisors (88208168197).

13120124202203 is an equidigital number, since it uses as much as digits as its factorization.

13120124202203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1024437.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 13120124202203 its reverse (30220242102131), we get a palindrome (43340366304334).

The spelling of 13120124202203 in words is "thirteen trillion, one hundred twenty billion, one hundred twenty-four million, two hundred two thousand, two hundred three".

Divisors: 1 149 94727 929561 14114323 138504589 88054524847 13120124202203