1312031113 has 4 divisors (see below), whose sum is σ = 1369075968. Its totient is φ = 1254986260.

The previous prime is 1312031101. The next prime is 1312031141. The reversal of 1312031113 is 3111302131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3111302131 = 7 ⋅444471733.

It is not a de Polignac number, because 1312031113 - 2²⁵ = 1278476681 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1312031153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28522393 + ... + 28522438.

It is an arithmetic number, because the mean of its divisors is an integer number (342268992).

Almost surely, 2^1312031113 is an apocalyptic number.

It is an amenable number.

1312031113 is a deficient number, since it is larger than the sum of its proper divisors (57044855).

1312031113 is an equidigital number, since it uses as much as digits as its factorization.

1312031113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 57044854.

The product of its (nonzero) digits is 54, while the sum is 16.

The square root of 1312031113 is about 36221.9700320123. The cubic root of 1312031113 is about 1094.7493885164.

Adding to 1312031113 its reverse (3111302131), we get a palindrome (4423333244).

The spelling of 1312031113 in words is "one billion, three hundred twelve million, thirty-one thousand, one hundred thirteen".