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1312040003 = 1969054737
BaseRepresentation
bin100111000110100…
…0010010001000011
310101102211112112012
41032031002101003
510141340240003
6334105323135
744341104341
oct11615022103
93342745465
101312040003
1161368108a
123074964ab
1317ba92241
14c6376991
157a2bc8d8
hex4e342443

1312040003 has 4 divisors (see below), whose sum is σ = 1381094760. Its totient is φ = 1242985248.

The previous prime is 1312039933. The next prime is 1312040021. The reversal of 1312040003 is 3000402131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1312040003 - 214 = 1312023619 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1312040003.

It is not an unprimeable number, because it can be changed into a prime (1312042003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34527350 + ... + 34527387.

It is an arithmetic number, because the mean of its divisors is an integer number (345273690).

Almost surely, 21312040003 is an apocalyptic number.

1312040003 is a deficient number, since it is larger than the sum of its proper divisors (69054757).

1312040003 is an equidigital number, since it uses as much as digits as its factorization.

1312040003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 69054756.

The product of its (nonzero) digits is 72, while the sum is 14.

The square root of 1312040003 is about 36222.0927473828. The cubic root of 1312040003 is about 1094.7518610950.

Adding to 1312040003 its reverse (3000402131), we get a palindrome (4312442134).

The spelling of 1312040003 in words is "one billion, three hundred twelve million, forty thousand, three".

Divisors: 1 19 69054737 1312040003