13120408241 has 4 divisors (see below), whose sum is σ = 13130356800. Its totient is φ = 13110459684.

The previous prime is 13120408003. The next prime is 13120408247. The reversal of 13120408241 is 14280402131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13120408241 is a prime.

It is a super-2 number, since 2×13120408241² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13120408241.

It is not an unprimeable number, because it can be changed into a prime (13120408247) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4972301 + ... + 4974938.

It is an arithmetic number, because the mean of its divisors is an integer number (3282589200).

Almost surely, 2^13120408241 is an apocalyptic number.

It is an amenable number.

13120408241 is a deficient number, since it is larger than the sum of its proper divisors (9948559).

13120408241 is an equidigital number, since it uses as much as digits as its factorization.

13120408241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9948558.

The product of its (nonzero) digits is 1536, while the sum is 26.

The spelling of 13120408241 in words is "thirteen billion, one hundred twenty million, four hundred eight thousand, two hundred forty-one".