Base | Representation |
---|---|
bin | 1011111011101101011010… |
… | …1001111100100110010011 |
3 | 1201110022010102111200101020 |
4 | 2332323112221330212103 |
5 | 3204431120422123243 |
6 | 43523235404210523 |
7 | 2522630344102212 |
oct | 276732651744623 |
9 | 51408112450336 |
10 | 13120431442323 |
11 | 41a9386555917 |
12 | 157a9b1b39a43 |
13 | 7423363726aa |
14 | 335064799079 |
15 | 17b45c462283 |
hex | beed6a7c993 |
13120431442323 has 4 divisors (see below), whose sum is σ = 17493908589768. Its totient is φ = 8746954294880.
The previous prime is 13120431442319. The next prime is 13120431442351. The reversal of 13120431442323 is 32324413402131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13120431442323 - 22 = 13120431442319 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13120431442373) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2186738573718 + ... + 2186738573723.
It is an arithmetic number, because the mean of its divisors is an integer number (4373477147442).
Almost surely, 213120431442323 is an apocalyptic number.
13120431442323 is a deficient number, since it is larger than the sum of its proper divisors (4373477147445).
13120431442323 is an equidigital number, since it uses as much as digits as its factorization.
13120431442323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4373477147444.
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 13120431442323 its reverse (32324413402131), we get a palindrome (45444844844454).
The spelling of 13120431442323 in words is "thirteen trillion, one hundred twenty billion, four hundred thirty-one million, four hundred forty-two thousand, three hundred twenty-three".
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