13120432341041 has 4 divisors (see below), whose sum is σ = 13127062172400. Its totient is φ = 13113802509684.

The previous prime is 13120432340969. The next prime is 13120432341139. The reversal of 13120432341041 is 14014323402131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13120432341041 - 2²² = 13120428146737 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13120432340995 and 13120432341013.

It is not an unprimeable number, because it can be changed into a prime (13120432346041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3314912711 + ... + 3314916668.

It is an arithmetic number, because the mean of its divisors is an integer number (3281765543100).

Almost surely, 2^{13120432341041} is an apocalyptic number.

It is an amenable number.

13120432341041 is a deficient number, since it is larger than the sum of its proper divisors (6629831359).

13120432341041 is an equidigital number, since it uses as much as digits as its factorization.

13120432341041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6629831358.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 13120432341041 its reverse (14014323402131), we get a palindrome (27134755743172).

The spelling of 13120432341041 in words is "thirteen trillion, one hundred twenty billion, four hundred thirty-two million, three hundred forty-one thousand, forty-one".