13120440203 has 4 divisors (see below), whose sum is σ = 14129704848. Its totient is φ = 12111175560.

The previous prime is 13120440197. The next prime is 13120440227. The reversal of 13120440203 is 30204402131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30204402131 = 983 ⋅30726757.

It is a cyclic number.

It is not a de Polignac number, because 13120440203 - 2⁸ = 13120439947 is a prime.

It is a super-2 number, since 2×13120440203² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13120440233) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 504632303 + ... + 504632328.

It is an arithmetic number, because the mean of its divisors is an integer number (3532426212).

Almost surely, 2^13120440203 is an apocalyptic number.

13120440203 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

13120440203 is a deficient number, since it is larger than the sum of its proper divisors (1009264645).

13120440203 is a wasteful number, since it uses less digits than its factorization.

13120440203 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1009264644.

The product of its (nonzero) digits is 576, while the sum is 20.

Adding to 13120440203 its reverse (30204402131), we get a palindrome (43324842334).

The spelling of 13120440203 in words is "thirteen billion, one hundred twenty million, four hundred forty thousand, two hundred three".