Base | Representation |
---|---|
bin | 11101110101010010001110… |
… | …011001111011110101001001 |
3 | 122012120002011112102011010222 |
4 | 131311102032121323311021 |
5 | 114144130420312342140 |
6 | 1143014433512115425 |
7 | 36431152311554111 |
oct | 3565221631736511 |
9 | 565502145364128 |
10 | 131205050121545 |
11 | 38895827315394 |
12 | 12870501995b75 |
13 | 58297771ca29a |
14 | 24585032b4041 |
15 | 1027e277db5b5 |
hex | 77548e67bd49 |
131205050121545 has 4 divisors (see below), whose sum is σ = 157446060145860. Its totient is φ = 104964040097232.
The previous prime is 131205050121533. The next prime is 131205050121599. The reversal of 131205050121545 is 545121050502131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 19494017531209 + 111711032590336 = 4415203^2 + 10569344^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131205050121545 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13120505012150 + ... + 13120505012159.
It is an arithmetic number, because the mean of its divisors is an integer number (39361515036465).
Almost surely, 2131205050121545 is an apocalyptic number.
It is an amenable number.
131205050121545 is a deficient number, since it is larger than the sum of its proper divisors (26241010024315).
131205050121545 is an equidigital number, since it uses as much as digits as its factorization.
131205050121545 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26241010024314.
The product of its (nonzero) digits is 30000, while the sum is 35.
The spelling of 131205050121545 in words is "one hundred thirty-one trillion, two hundred five billion, fifty million, one hundred twenty-one thousand, five hundred forty-five".
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