131210000323 has 4 divisors (see below), whose sum is σ = 131214930480. Its totient is φ = 131205070168.

The previous prime is 131210000309. The next prime is 131210000371. The reversal of 131210000323 is 323000012131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131210000323 - 2¹³ = 131209992131 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131210000297 and 131210000306.

It is not an unprimeable number, because it can be changed into a prime (131210000303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2424940 + ... + 2478457.

It is an arithmetic number, because the mean of its divisors is an integer number (32803732620).

Almost surely, 2^131210000323 is an apocalyptic number.

131210000323 is a deficient number, since it is larger than the sum of its proper divisors (4930157).

131210000323 is an equidigital number, since it uses as much as digits as its factorization.

131210000323 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4930156.

The product of its (nonzero) digits is 108, while the sum is 16.

Adding to 131210000323 its reverse (323000012131), we get a palindrome (454210012454).

The spelling of 131210000323 in words is "one hundred thirty-one billion, two hundred ten million, three hundred twenty-three", and thus it is an aban number.