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131210003010131 = 595181220453951
BaseRepresentation
bin11101110101010110110101…
…100111101101001001010011
3122012120112221201010221222222
4131311112311213231021103
5114144221041232311011
61143021013201451255
736431416122454403
oct3565266547551123
9565515851127888
10131210003010131
1138897939074941
1212871464640b2b
13582a0863724a6
142458852dd0803
151028117538ddb
hex7755b59ed253

131210003010131 has 4 divisors (see below), whose sum is σ = 131210224059264. Its totient is φ = 131209781961000.

The previous prime is 131210003010019. The next prime is 131210003010199. The reversal of 131210003010131 is 131010300012131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131210003010131 - 218 = 131210002747987 is a prime.

It is a super-2 number, since 2×1312100030101312 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131210003010631) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 109631795 + ... + 110822156.

It is an arithmetic number, because the mean of its divisors is an integer number (32802556014816).

Almost surely, 2131210003010131 is an apocalyptic number.

131210003010131 is a deficient number, since it is larger than the sum of its proper divisors (221049133).

131210003010131 is an equidigital number, since it uses as much as digits as its factorization.

131210003010131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 221049132.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 131210003010131 its reverse (131010300012131), we get a palindrome (262220303022262).

The spelling of 131210003010131 in words is "one hundred thirty-one trillion, two hundred ten billion, three million, ten thousand, one hundred thirty-one".

Divisors: 1 595181 220453951 131210003010131