Base | Representation |
---|---|
bin | 10011000101111111010… |
… | …001001010011101011011 |
3 | 11122102202112001212122222 |
4 | 103011333101022131123 |
5 | 132444140124343003 |
6 | 2442434233334255 |
7 | 163540031641652 |
oct | 23057721123533 |
9 | 4572675055588 |
10 | 1312100231003 |
11 | 466505412901 |
12 | 19236386738b |
13 | 96965c53943 |
14 | 47712618199 |
15 | 241e6393c38 |
hex | 1317f44a75b |
1312100231003 has 4 divisors (see below), whose sum is σ = 1312312791888. Its totient is φ = 1311887670120.
The previous prime is 1312100230999. The next prime is 1312100231009. The reversal of 1312100231003 is 3001320012131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1312100231003 - 22 = 1312100230999 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1312100231009) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 106271183 + ... + 106283528.
It is an arithmetic number, because the mean of its divisors is an integer number (328078197972).
Almost surely, 21312100231003 is an apocalyptic number.
1312100231003 is a deficient number, since it is larger than the sum of its proper divisors (212560885).
1312100231003 is an equidigital number, since it uses as much as digits as its factorization.
1312100231003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 212560884.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 1312100231003 its reverse (3001320012131), we get a palindrome (4313420243134).
The spelling of 1312100231003 in words is "one trillion, three hundred twelve billion, one hundred million, two hundred thirty-one thousand, three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •