13121011121113 has 4 divisors (see below), whose sum is σ = 14995441281280. Its totient is φ = 11246580960948.

The previous prime is 13121011121111. The next prime is 13121011121171. The reversal of 13121011121113 is 31112111012131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13121011121113 - 2¹ = 13121011121111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13121011121111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 937215080073 + ... + 937215080086.

It is an arithmetic number, because the mean of its divisors is an integer number (3748860320320).

Almost surely, 2^{13121011121113} is an apocalyptic number.

It is an amenable number.

13121011121113 is a deficient number, since it is larger than the sum of its proper divisors (1874430160167).

13121011121113 is an equidigital number, since it uses as much as digits as its factorization.

13121011121113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1874430160166.

The product of its (nonzero) digits is 36, while the sum is 19.

Adding to 13121011121113 its reverse (31112111012131), we get a palindrome (44233122133244).

The spelling of 13121011121113 in words is "thirteen trillion, one hundred twenty-one billion, eleven million, one hundred twenty-one thousand, one hundred thirteen".