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131210214323 = 664911973353
BaseRepresentation
bin111101000110010111…
…1001111101110110011
3110112200021011111120112
41322030233033232303
54122204303324243
6140135510131535
712323340263666
oct1721457175663
9415607144515
10131210214323
1150711822061
122151a050bab
13c4b0834296
1464ca0d76dd
15362e21a818
hex1e8cbcfbb3

131210214323 has 4 divisors (see below), whose sum is σ = 131212254168. Its totient is φ = 131208174480.

The previous prime is 131210214301. The next prime is 131210214337. The reversal of 131210214323 is 323412012131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131210214323 - 28 = 131210214067 is a prime.

It is a super-2 number, since 2×1312102143232 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131210214353) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 920186 + ... + 1053167.

It is an arithmetic number, because the mean of its divisors is an integer number (32803063542).

Almost surely, 2131210214323 is an apocalyptic number.

131210214323 is a deficient number, since it is larger than the sum of its proper divisors (2039845).

131210214323 is an equidigital number, since it uses as much as digits as its factorization.

131210214323 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2039844.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 131210214323 its reverse (323412012131), we get a palindrome (454622226454).

The spelling of 131210214323 in words is "one hundred thirty-one billion, two hundred ten million, two hundred fourteen thousand, three hundred twenty-three".

Divisors: 1 66491 1973353 131210214323