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1312110011131 = 1936798497467
BaseRepresentation
bin10011000101111111110…
…110011110001011111011
311122102210012110202110221
4103011333312132023323
5132444200130324011
62442435223120511
7163540211034313
oct23057766361373
94572705422427
101312110011131
1146650a992857
12192366ba3137
1396967c993ba
1447713a42443
15241e7176971
hex1317fd9e2fb

1312110011131 has 4 divisors (see below), whose sum is σ = 1318908508792. Its totient is φ = 1305311513472.

The previous prime is 1312110011123. The next prime is 1312110011143. The reversal of 1312110011131 is 1311100112131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1312110011131 - 23 = 1312110011123 is a prime.

It is a super-2 number, since 2×13121100111312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1312110011101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3399248541 + ... + 3399248926.

It is an arithmetic number, because the mean of its divisors is an integer number (329727127198).

Almost surely, 21312110011131 is an apocalyptic number.

1312110011131 is a deficient number, since it is larger than the sum of its proper divisors (6798497661).

1312110011131 is an equidigital number, since it uses as much as digits as its factorization.

1312110011131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6798497660.

The product of its (nonzero) digits is 18, while the sum is 16.

Adding to 1312110011131 its reverse (1311100112131), we get a palindrome (2623210123262).

The spelling of 1312110011131 in words is "one trillion, three hundred twelve billion, one hundred ten million, eleven thousand, one hundred thirty-one".

Divisors: 1 193 6798497467 1312110011131