Base | Representation |
---|---|
bin | 111101000110011001… |
… | …0010010111110010001 |
3 | 110112200022200010120102 |
4 | 1322030302102332101 |
5 | 4122210004422113 |
6 | 140135535222145 |
7 | 12323350134341 |
oct | 1721462227621 |
9 | 415608603512 |
10 | 131211014033 |
11 | 50712218980 |
12 | 2151a377955 |
13 | c4b0a54298 |
14 | 64ca264d21 |
15 | 362e327758 |
hex | 1e8cc92f91 |
131211014033 has 16 divisors (see below), whose sum is σ = 146867398656. Its totient is φ = 116191106640.
The previous prime is 131211014003. The next prime is 131211014047. The reversal of 131211014033 is 330410112131.
It is a cyclic number.
It is not a de Polignac number, because 131211014033 - 214 = 131210997649 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131211013996 and 131211014014.
It is not an unprimeable number, because it can be changed into a prime (131211014003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 204341 + ... + 551522.
It is an arithmetic number, because the mean of its divisors is an integer number (9179212416).
Almost surely, 2131211014033 is an apocalyptic number.
It is an amenable number.
131211014033 is a deficient number, since it is larger than the sum of its proper divisors (15656384623).
131211014033 is a wasteful number, since it uses less digits than its factorization.
131211014033 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 756284.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 131211014033 its reverse (330410112131), we get a palindrome (461621126164).
The spelling of 131211014033 in words is "one hundred thirty-one billion, two hundred eleven million, fourteen thousand, thirty-three".
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